CS Atlas GATE 2027
Algorithms course
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Algorithms/Phase 2 · Searching & Hashing

Chapter review LI-2.1 · Item 24 of 79

Searching

Read at your own pace. Try the questions before opening the answers.

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ACompressed recap

🧾

Linear search Θ(n) (best 1, worst n, average (n+1)/2). Binary search on a sorted, randomly accessible array: mid = ⌊(lo+hi)/2⌋, ≤ ⌊log n⌋ + 1 probes, Θ(log n), invariant "x ∈ A[lo..hi] if present"; Θ(n) on linked lists. Variants: first/last occurrence (keep searching left/right on equality), count = last − first + 1, lower bound, rotated arrays, search on a monotone answer. Comparison-based search needs Ω(log n).

BMerged rule card

2.1.1 Linear search and binary search: comparisons and correctness

  • Linear search: Θ(n); best 1, worst n, average (n+1)/2.
  • Binary search: sorted + random access; ≤ ⌊log n⌋ + 1 probes; Θ(log n); iterative O(1) space.
  • Invariant: x, if present, lies in A[lo..hi]. mid = ⌊(lo+hi)/2⌋.
  • On a linked list binary search is Θ(n).

2.1.2 Binary search variants and the Ω(log n) lower bound for searching

  • First occurrence: equal → record, go left. Last: equal → record, go right. Count = last − first + 1.
  • Lower bound: first index with A[i] ≥ x (the final lo).
  • Rotated array: one half is sorted at every step.
  • Comparison-based search: Ω(log n) (decision tree with ≥ n leaves).

CInterleaved GATE-style questions

Q1NAT1 markProbes

In B = [3, 8, 15, 21, 27, 34, 40, 46, 52, 60, 71], how many probes to find 3?

Numerical answer: ________

Q2NAT1 markMax probes

Maximum probes of binary search on 100 elements?

Numerical answer: ________

Q3NAT2 marksProbes on 31

A sorted array has 31 elements. How many elements need exactly 5 probes to be found?

Numerical answer: ________

Q4MCQ1 markRequirement

Binary search runs in O(log n) only if the data:

  • (A) is sorted and stored in an array
  • (B) has distinct elements
  • (C) is sorted and stored in a linked list
  • (D) is a heap

Q5NAT2 marksLast occurrence

A = [2, 4, 4, 4, 7, 9, 9, 12]. Index (0-based) of the last 9?

Numerical answer: ________

Q6NAT1 markLower bound

A = [2, 4, 4, 4, 7, 9, 9, 12]. First index with A[i] ≥ 5?

Numerical answer: ________

Q7MCQ1 markCounting

The fastest way to count occurrences of x in a sorted array of n elements is:

  • (A) two binary searches, Θ(log n)
  • (B) one binary search then scan both ways, always Θ(log n)
  • (C) Θ(n) scan
  • (D) hashing all elements first, Θ(1)

Q8NAT2 marksDecision tree

Minimum worst-case comparisons (two-way) to identify the position of a key among 5,000 sorted elements?

Numerical answer: ________

DAnswer Vault

Answer Vault

Try the questions first. Open when you are ready to check.

Q1 Answer: 31 mark

34 → 15 → 3.

Re-read: Lesson 2.1.1 — Linear search and binary search: comparisons and correctness

Q2 Answer: 71 mark

⌊log 100⌋ + 1.

Re-read: Lesson 2.1.1 — Linear search and binary search: comparisons and correctness

Q3 Answer: 162 marks

The decision tree is perfect with levels of 1, 2, 4, 8, 16 nodes.

Re-read: Lesson 2.1.1 — Linear search and binary search: comparisons and correctness

Q4 Answer: (A)1 mark

Needs order and random access.

  • (B) is wrong: Duplicates are fine.
  • (C) is wrong: Middle elements cost Θ(n) to reach.
  • (D) is wrong: A heap is not sorted.

Re-read: Lesson 2.1.1 — Linear search and binary search: comparisons and correctness

Q5 Answer: 62 marks

A[6] = 9.

Re-read: Lesson 2.1.2 — Binary search variants and the Ω(log n) lower bound for searching

Q6 Answer: 41 mark

A[4] = 7.

Re-read: Lesson 2.1.2 — Binary search variants and the Ω(log n) lower bound for searching

Q7 Answer: (A)1 mark

First and last occurrence.

  • (B) is wrong: The scan can be Θ(n).
  • (C) is wrong: Slower.
  • (D) is wrong: Building the table costs Θ(n).

Re-read: Lesson 2.1.2 — Binary search variants and the Ω(log n) lower bound for searching

Q8 Answer: 132 marks

⌈log 5000⌉ = 13.

Re-read: Lesson 2.1.2 — Binary search variants and the Ω(log n) lower bound for searching

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