Notes
Twelve questions from every phase, in random order. Do them without notes, then check and reveal.
Practice questions
- NAT · 1 mark
Transmission delay (ms) of a 1250-byte packet on a 25 Mbps link?
Write your answer before opening the key.
- MCQ · 1 mark
Which device works up to the data link layer?
- Hub
- Switch
- Router
- Repeater
- NAT · 1 mark
Maximum throughput of pure ALOHA, in percent (1 decimal)?
Write your answer before opening the key.
- NAT · 1 mark
Usable hosts in a /29 subnet?
Write your answer before opening the key.
- MCQ · 2 marks
Network address of 10.1.77.200/19?
- 10.1.64.0
- 10.1.72.0
- 10.1.77.0
- 10.1.0.0
- NAT · 2 marks
A 2400-byte datagram (20-byte header) meets an MTU of 1000. How many fragments?
Write your answer before opening the key.
- NAT · 1 mark
Stop-and-wait efficiency when a = 2 (3 decimals)?
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- NAT · 1 mark
Maximum Go-Back-N sender window with 4-bit sequence numbers?
Write your answer before opening the key.
- NAT · 1 mark
A client's SYN carries ISN 5000. Sequence number of its first data byte after the handshake?
Write your answer before opening the key.
- MCQ · 1 mark
Which DNS record names a domain's mail server?
- A
- MX
- CNAME
- NS
- NAT · 1 mark
Internet checksum (decimal) of the 16-bit words 0x1111 and 0x2222?
Write your answer before opening the key.
- NAT · 1 mark
Persistent HTTP without pipelining: base + 3 small objects, RTT 10 ms. Total ms?
Write your answer before opening the key.
Answer key
Try the questions first. Open when you are ready to check.
- 0.4 — 10,000 bits / 25 × 10⁶ = 0.4 ms.
- B — Switches read link headers.
- A: Layer 1.
- C: Layer 3.
- D: Layer 1.
- 18.3..18.5 — 1/(2e) = 18.4 %.
- 6 — 2³ − 2 = 6.
- A — Block size in the third octet = 32: 77 lies in 64–95 → 10.1.64.0.
- B: That is a /21 boundary.
- C: That is a /24 boundary.
- D: That is a /16 boundary.
- 3 — Max data 976 (multiple of 8); 2380 = 976 + 976 + 428 → 3.
- 0.2 — 1/(1 + 4) = 0.2.
- 15 — 2⁴ − 1 = 15.
- 5001 — The SYN consumes one sequence number.
- B — MX.
- A: Address.
- C: Alias.
- D: Name server.
- 52428 — Sum 0x3333 → complement 0xCCCC = 52428.
- 50 — 2 RTT + 3 RTT = 50 ms.