CS Atlas GATE 2027
Computer Networks course
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Computer Networks/Phase 6 · Integration & Final Test

Revision 6.2.1 · Item 86 of 90

Mixed practice set 1

Read at your own pace. Try the questions before opening the answers.

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Notes

Twelve questions from every phase, in random order. Do them without notes, then check and reveal.

Practice questions

  1. NAT · 1 mark

    Transmission delay (ms) of a 1250-byte packet on a 25 Mbps link?

    Write your answer before opening the key.

  2. MCQ · 1 mark

    Which device works up to the data link layer?

    1. Hub
    2. Switch
    3. Router
    4. Repeater
  3. NAT · 1 mark

    Maximum throughput of pure ALOHA, in percent (1 decimal)?

    Write your answer before opening the key.

  4. NAT · 1 mark

    Usable hosts in a /29 subnet?

    Write your answer before opening the key.

  5. MCQ · 2 marks

    Network address of 10.1.77.200/19?

    1. 10.1.64.0
    2. 10.1.72.0
    3. 10.1.77.0
    4. 10.1.0.0
  6. NAT · 2 marks

    A 2400-byte datagram (20-byte header) meets an MTU of 1000. How many fragments?

    Write your answer before opening the key.

  7. NAT · 1 mark

    Stop-and-wait efficiency when a = 2 (3 decimals)?

    Write your answer before opening the key.

  8. NAT · 1 mark

    Maximum Go-Back-N sender window with 4-bit sequence numbers?

    Write your answer before opening the key.

  9. NAT · 1 mark

    A client's SYN carries ISN 5000. Sequence number of its first data byte after the handshake?

    Write your answer before opening the key.

  10. MCQ · 1 mark

    Which DNS record names a domain's mail server?

    1. A
    2. MX
    3. CNAME
    4. NS
  11. NAT · 1 mark

    Internet checksum (decimal) of the 16-bit words 0x1111 and 0x2222?

    Write your answer before opening the key.

  12. NAT · 1 mark

    Persistent HTTP without pipelining: base + 3 small objects, RTT 10 ms. Total ms?

    Write your answer before opening the key.

Answer key

Try the questions first. Open when you are ready to check.
  1. 0.4 — 10,000 bits / 25 × 10⁶ = 0.4 ms.

    Review lesson 1.3.1

  2. B — Switches read link headers.
    • A: Layer 1.
    • C: Layer 3.
    • D: Layer 1.

    Review lesson 1.1.3

  3. 18.3..18.5 — 1/(2e) = 18.4 %.

    Review lesson 2.3.2

  4. 6 — 2³ − 2 = 6.

    Review lesson 3.1.3

  5. A — Block size in the third octet = 32: 77 lies in 64–95 → 10.1.64.0.
    • B: That is a /21 boundary.
    • C: That is a /24 boundary.
    • D: That is a /16 boundary.

    Review lesson 3.1.4

  6. 3 — Max data 976 (multiple of 8); 2380 = 976 + 976 + 428 → 3.

    Review lesson 3.2.2

  7. 0.2 — 1/(1 + 4) = 0.2.

    Review lesson 4.2.1

  8. 15 — 2⁴ − 1 = 15.

    Review lesson 4.2.3

  9. 5001 — The SYN consumes one sequence number.

    Review lesson 4.3.2

  10. B — MX.
    • A: Address.
    • C: Alias.
    • D: Name server.

    Review lesson 5.2

  11. 52428 — Sum 0x3333 → complement 0xCCCC = 52428.

    Review lesson 2.2.3

  12. 50 — 2 RTT + 3 RTT = 50 ms.

    Review lesson 5.3

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